waterboy Posted March 20, 2008 Report Share Posted March 20, 2008 We have a Pentair 782/783 test kit. The instuctions for the water hardness state. 1) Add 2 drops of solution #6 to the water. (this solution is blue so the water is now blue) 2) Carefully add solution #7 (1) drop at a time, shaking vial between drops to mix. Count the number of drops it takes the red color to"just" change to pure blue color. My problem is the water is already blue from adding the 2 drops of #6 solution. My question is do I have the wrong color of #6 solution or should instruction 2 state "Carefully add solution #7 (1) drop at a time, shaking vial between drops to mix. Count the number of drops it takes the BLUE color to"just" change to pure RED color. I have emailed pentair and hope they will respond. Confused in BC thanks you in advance for your help. Quote Link to comment Share on other sites More sharing options...
Pathfinder Posted March 20, 2008 Report Share Posted March 20, 2008 In the taylor kits its blue from the start then count the drops till til changes red then multiply by 10 I believe pentair is the same. that is the colour you should end up with. Quote Link to comment Share on other sites More sharing options...
waterboy Posted March 20, 2008 Author Report Share Posted March 20, 2008 Thanks for you response Pathfinder. The pentair says multiply by 50 and I only added 3 drops of the #7 solution so I will try it tomorrow and add at least 8 drops to see if I can make it go red Quote Link to comment Share on other sites More sharing options...
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